Question

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s2, what is the radius of the circle?

0.60 m
1.2 m
0.36 m
0.84 m

Answer 1

I googled it and I think the answer is 0.60m

good luck!

Answer 2

By definition, the centripetal acceleration is given by:

`image`

Where,

v: tangential speed

r: radius of the circular path

Clearing the radio we have:

`image`

Substituting values we have:

`image`

Therefore, the radius of the circular path is equal to 0.60 meters.

Answer:

The radius of the circle is:

0.60 m

option1