Question

A fantasy board game makes use of four dice. The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

30



240



2,400



3,000

Answer 1

2,400 would be the best outcome

Answer 2

Answer: 2,400

Explanation:

Number of possible outcomes on a standard 6-faced die =6 (Equal to the number of faces on die)

Similarly, Number of possible outcomes on a standard 4-faced die =4

Number of possible outcomes on a standard 10-faced die =10

We apply the Fundamental principal of counting, that says that the total number of outcomes for a number of events is equal to the product of the possible outcomes of each event.

We get, the number of possible outcomes exist :-

`6*4*10*10\ \ \ [\ \because\ \text{ one 6-faced, one 4-faced and two 10-faced die]}`

`=2400`

Hence, the number of possible outcomes exist =2,400