A spring with a spring constant of 200 N/m stretches by 0.03 m. What is the potential energy of the spring?

asked May 16, 2022 216k views

25 votes

6.9k points

Please log in or register to add a comment.

5 votes

Answer: 0.09 J

Explanation: K = 200 N/m , 1/2 X 200 N/m X (0.03 M)^2 = 0.09 J

Igorgue answered May 21, 2022

7.3k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.5m questions

11.2m answers