Question

A force acts on a body of mass 13 kg initially at rest. The force

acts for 10 seconds, and once it quits, the body covers 60 min
the next 6 seconds. Find the force that acted on the body.

Answer 1

Force that acted on the body was F = 13 N

Step-by-step explanation:

If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s

When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:

`v_f=v_i+a*t`

which in our case becomes;

`10\,m/s=0+a*(10\,s)`

and we can solve for the acceleration as:

a = 10/10 m/s^2 = 1 m/s^2

Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:

F = 13 kg * 1 m/s^2 = 13 N