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How many atoms are there in .028g of Fe?

User Deep Arora
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2 Answers

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Hope this helps you!
How many atoms are there in .028g of Fe?-example-1
User Sujith Sandeep
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4 votes

Answer:


atomsFe=3.0x10^(20)atomsFe

Step-by-step explanation:

Hello,

In this case, considering that for iron the grams are related with moles via the atomic mass and the atoms with moles via the Avogadro's number, we develop the following proportional analysis to compute the required atoms:


atomsFe=0.028gFe*(1molFe)/(55.845gFe)*(6.022x10^(23)atomsFe)/(1molFe) \\atomsFe=3.0x10^(20)atomsFe

Best regards.

User Maroodb
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