Question

What is the height a football is

kicked when it leaves the players
foot at 30 m/s in a 29° angle?

Answer 1

Vy = V0 * sin θ vertical speed

Vy = 30 m/s * sin 29 = 14.5 m/s

t = 14.5 m/s / 9.8 m/s^2 = 1.48 sec time to reach max height

H = Vy t - 1/2 g t^2 acceleration is in opposite direction to initial Vy

H = 14.5 m/s * 1.48 s - 1/2 * 9.8 m/s^2 * (1.48 s)^2

H = 10.7 m

Answer 2

Assuming you are looking for the maximum height of the football during its flight, here the answer.

Answer: 10.78 meters

Steps:

Equation for maximum height reached:
H = Vo^2 * sin^2 θ / 2g

Note:
H = maximum height
Vo = initial velocity
θ = angle
g = gravity

Here is what we know
Vo = 30
θ = 29°
g = 9.81

Therefore

H = 30^2 * sin^2 (29) / 2 * 9.81

Now let’s solve for H step by step.
H = 900 * sin^2 (29) / 2 * 9.81
H = 900 * 0.23504036 / 19.62
H = 211.53633109 / 1962
H = 10.78166825

H = 10.78 meters