Answer:
Vy = V0 * sin θ vertical speed
Vy = 30 m/s * sin 29 = 14.5 m/s
t = 14.5 m/s / 9.8 m/s^2 = 1.48 sec time to reach max height
H = Vy t - 1/2 g t^2 acceleration is in opposite direction to initial Vy
H = 14.5 m/s * 1.48 s - 1/2 * 9.8 m/s^2 * (1.48 s)^2
H = 10.7 m