Question

How many moles of HNO3 will be produced when .65 grams of N2O5 reacts?

Answer 1

Here is the balanced equation:
N2O5 + H2O -> 2 HNO3

It is a 1:2 ratio between the moles of N2O5 and HNO3

To work out the number of moles of N2O5 used, we must divide the mass of the substance (in grams) by the molecular mass

In this case, the molecular mass of DiNitrogen Pentoxide is 2(14) + 5(16) = 108 amu

So, when we divide 0.65 by 108, we get 6.02 x 10^-3

Since, as I mentioned before, it is a 1:2 ratio, all we have to do now is multiply this number by 2

So, we produce approximately 0.012 moles of Nitric acid

Don't hesitate to ask any further questions!
Hope I helped!! xx

Answer 2

0.012036 moles of nitric acid will be produced when 0.65 grams of dinitrogen pentoxide reacts.

Step-by-step explanation:

`N_2O_5+H_2O\rightarrow 2HNO_3`

Moles of dinitrogen pentoxide =
`(0.65 g)/(108 g/mol)=0.006018 mol`

According to recation , 1 mole of dinitrogen pentoxide gives 2 moles of nitric acid.

Then 0.006018 moles of dinitrogen pentoxide will give:

`(2)/(1)* 0.006018mol=0.012036 mol` of nitric acid

0.012036 moles of nitric acid will be produced when 0.65 grams of dinitrogen pentoxide reacts.