Question

How do I establish this identity??

Answer 1

`\frac{cosec\theta+cotan\theta} {sec\theta+tan\theta}=\frac{cosec\theta+cotan\theta} {sec\theta+tan\theta}*(cosec\theta-cotan\theta)/(cosec\theta-cotan\theta)*\frac{sec\theta-tan\theta} {sec\theta-tan\theta}`

And use that,


`\sec^2\theta-\tan^2\theta=1`


`cosec^2\theta-cotan^2\theta=1`