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Question regarding limits to see if my procedure of getting the answer is right!!!!

Limit x-> 0

Tan(x^2)
---------------
x

I know it's indeterminate so I need find another way


So I did the tan identity

cosx^2
----------
sinx^2
------------------------
x


cosx^2 1
------------ * ------
sinx^2 x


cosx^2
-----------
sinx^3


I don't know what to do, but I know that it has to be 0. Any ideas?

1 Answer

5 votes

\displaystyle\lim_(x\to0)\frac{\tan x^2}x=\lim_(x\to0)x(\tan x^2)/(x^2)=\lim_(x\to0)\frac x{\cos x^2}*\lim_(x\to0)(\sin x^2)/(x^2)

Recall that


\displaystyle\lim_(x\to0)\frac{\sin x}x=1

and so replacing
x with
x^2, you get that the second limit is 1. Meanwhile,


\displaystyle\lim_(x\to0)\frac x{\cos x^2}=\frac01=0

so the limit is 0.
User Hieu Le
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