Register
An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m ?
101k views
5 votes
An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m ?

User IceWhisper
by
8.4k points

2 Answers

3 votes

Answer:

t=14.14 seconds

Step-by-step explanation:

User Doosh
by
7.6k points
6 votes
Vf^2 = Vi^2 + 2ad
a= 34 m/s^2
Vi = 0 m/s
d = 3400m

Vf = 480.83 m/s

a=v/t
t=v/a
t=480.83/34
t=14.142 s
User Zahid Nisar
by
8.5k points
← Prev Question Next Question →

Related questions

User Charri
asked Feb 6, 2020 98.8k views
What is the change in elevation from 8500m to 3400m
Charri asked Feb 6, 2020
by Charri
8.5k points
2 answers
5 votes
98.8k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

At sea level, water boils at 100 degrees celcius and methane  boiled at -161 degrees celcius. Which of these substances has a stronger force of attraction between its particles? Explain your answer
Physical properties of minerals graphic organizer
What type of rock is the Haystack rock (igneous, Metamorphic, or Sedimentary)
How many light sources do you know Pls list them
What is the minimum resistance which can be made using five resistors each of 1/5
Link Copied!