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This is my last question can someone help me with my homework.

This is my last question can someone help me with my homework.-example-1

1 Answer

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Answer:

C, A, A

Explanation:

In general, you ...

  • identify the coefficients of one of the variables
  • swap them, and negate one of them
  • multiply the corresponding equations by the "adjusted" coefficients.

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In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:

multiply equation 2 by -4 . . . (eliminates x)

Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:

multiply equation 1 by 3 . . . (eliminates y)

These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.

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The other problems are worked in a similar fashion.

This is my last question can someone help me with my homework.-example-1
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