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The acceleration of a particle is directly proportional to the square of Problems 615

the time t. When t 5 0, the particle is at x 5 24 m. Knowing that at
t 5 6 s, x 5 96 m and v 5 18 m/s, express x and v in terms of t. ((mechanics))

User LarsTech
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1 Answer

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answer

x(t) = t^4/108 + 10t + 24, v(t) = t^3/27 + 10
User Jeff Treuting
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