Question

What are the possible values of x if (4x-5)^2=49? check all that apply. -4/5, -1/2, 3, 5, 7

Answer 1

To solve an equation with a square yo would take the square root of both sides.
(4x - 5)^2 = 49
sqrt((4x - 5)^2) = sqrt49
4x - 5 = + - 7
4x - 5 = 7 and 4x - 5 = -7
4x = 12 4x = -2
x = 3 x = -1/2

Answer 2

The possible values of x satisfying the equation (4x-5)²=49 are x = 3 and x = -1/2. We find these by taking the square root of both sides of the equation and solving the resulting linear equations.

The student has asked for the possible values of x if (4x-5)²=49. To find these values, we start by taking the square root of both sides of the equation, which gives us two possible equations:

4x - 5 = 7

4x - 5 = -7

Solving the first equation for x yields:

4x = 12

x = 3

Solving the second equation for x yields:

4x = -2

x = -1/2

So, the solutions to the equation are x=3 and =1/−2. These values correspond to options C and B, respectively.

Thus, the possible values of x are C. x = 3 and B. x = -1/2.

COMPLETE QUESTION:

What are the possible values of x if (4x-5)²=49? check all that apply.

A. X = -4/5,

B. X = -1/2,

C. X = 3,

D. X = 5,

E. X = 7