P(x)=5x^3+3x^2−6x−4. q(x)=3x^3−2x^2−x+3. r(x)=−x^3+2x^2−3x+7. What is p(x)−q(x)+r(x) ?

asked Sep 1, 2018 213k views

5 votes

P(x)=5x^3+3x^2−6x−4.

q(x)=3x^3−2x^2−x+3.

r(x)=−x^3+2x^2−3x+7.

What is p(x)−q(x)+r(x) ?

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3 votes

Answer:

3x^(3) + 7x^(2) - 8x

Explanation:

p(x) + q(x) - r(x)

(5x^(3) + 3x^(2) - 6x - 4) - (3x^(3) -2x^(2) - x + 3) + (x^(3) + 2x^(2) - 3x + 7)

5x^(3) + 3x^(2) - 6x - 4 - 3x^(3) + 2x^(2) + x - 3 + x^(3) + 2x^(2) - 3x + 7

3x^(3) + 7x^(2) - 8x

PRS answered Sep 5, 2018

by PRS

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