Question

When 10 grams of copper and 10 grams of iodine are mixed, what is the

theoretical yield of copper I iodide?
2Cu + I2 → 2CuI

30 grams

15 grams

7.5 grams

20 grams

Answer 1

The answer is B) 15 grams

Answer 2

15 grams

Step-by-step explanation:

Mass of Cu = 10 g

Molar mass of Cu = 63.546 g/mol

Moles of Cu =
`(10 g)/(63.546 g/mol)` = 0.1574

Mass of I₂ = 10 g

Molar mass of I₂ = 253.8 g/mol

Moles of I₂ =
`(10 g)/(253.8 g/mol )` = 0.04

I₂ here is the limiting reactant as it has the least number of moles.

Based on the balanced equation,

1 mole of I₂ = 2 moles of CuI

0.04 mole of I₂ = 0.08 moles of CuI

Molar mass of CuI = 190.45 g/mol

Mass of CuI = 0.08 moles x 190.45 g/mol = 15.236 g