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If P(A)= 0.3 and P(B|A)=0.9 what is P(A B)?

User Dmyan
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1 Answer

3 votes
You seem to be missing a symbol, which I assume is intersection
\cap.

From the definition of conditional probability,


\mathbb P(B|A)=(\mathbb P(B\cap A))/(\mathbb P(A))\implies0.9=(\mathbb P(B\cap A))/(0.3)\implies\mathbb P(B\cap A)=0.27
User Shashikant Kore
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