Question

A force of 60 N is applied to a skier to pull him along a horizontal surface so that his speed remains constant. If the coefficient of friction of the skis on snow is 0.05, then what is the weight of the skier?

Answer 1

`1200\ \text{N}`

Step-by-step explanation:

F = Force on the skier = 60 N

`\mu` = Coefficient of friction = 0.05

w = Weight of skier

Force is given by

`F=\mu w`

`\Rightarrow w=(F)/(\mu)`

`\Rightarrow w=(60)/(0.05)=(6000)/(5)`

`\Rightarrow w=1200\ \text{N}`

Weight of the skier on which the force is being applied is
`1200\ \text{N}` .