Question

Given that 1/2 and -3 are the roots of the equation 0=ax^2+bx+c find a,b and c are the least possible integer

Answer 1

2x^2 + 5x - 3=0

Explanation:

using:

x^2-x(1/2 +(-3) +1/2 ×-3=0

x^2-x(-5/2) -3/2 =0

multiply both sides by 2

x^2+ 5/2x*2 -3/2*2=0*2

2x^2 +5x - 3 =0