Answer:
a) 0.1353
b) attached below
c) 7.4
Step-by-step explanation:
Frame transmission rate = 40 msec
Total load requests = 50 requests /sec
hence
Total arrival rate G in Frames ( G ) / x secs
= 50 request/sec * X sec
= 50 * ( 40*10^-3 )
= 2 requests/ x sec
a) Determine chance of success on first attempt
0.1353
b) Determine the probability of exactly K collisions followed by a success
attached below
c) what is the expected number of transmission attempts needed
7.4