Question

A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?

Answer 1

Δp = 620 N.s

Step-by-step explanation:

• Newton's second law, was originally conceived as follows:

`F = (\Delta p)/(\Delta t) (1)`

• In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.

for m= constant, it reduces to F= m*a.

• Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:

`\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)`