Question

What volume of 1.25M HCl would be required to prepare 180 mL of a 0.500M HCl solution?

Answer 1

the volume required of 1.25M HCL to prepare 180ml of a 0.500M Hcl solution is 72ml

Answer 2

Volume of 1.25 M HCl required = 72 mL.

Step-by-step explanation:

This is a dilution concept.

It is that if we dilute a solution, the number of moles of solute will remain the same in the diluted solution. It is the moles per unit volume which changes on dilution.

So after dilution the moles of HCl present will be :

Moles = molarity X volume = 0.500 X 180 mL = 0.500 X 0.18 L = 0.09 moles

this is the moles present before dilution

moles before dilution required = 0.09 = molarity X volume

volume of concentrated solution required = moles / molarity = 0.09 / 1.25

volume of 1.25 M solution required = 0.072 L = 72mL