Question

If mZABD = 70°, what are mZABC and mZDBC?

mZABC=
mZDBC=
(6x+3) D
B
(9x-8)
Please help me

Answer 1

Explanation:

ABD = ABC + DBC

Eqivalent to:

78 = (5x + 3) + (5x - 5)

78 = 5x + 5x + 3 - 5

78 = 10x - 2

80 = 10x (move -2 to the left side and get 78 + 2 = 80)

8 = x (80/10 = 8)

With x = 8,

ABC = 5x - 5 = 8*5 - 5 = 40 - 5 = 35

DBC = 5x +3 = 8*5 + 3 = 40 + 3 = 43