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If an object is projected vertically upward from ground level with an initial velocity of 320 ft/sec, then its distance s above the ground after t seconds is given by s=-16t^2+320t. For what values of t will the object be more than 1536 feet above the ground?

User CruelIO
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2 Answers

1 vote
t>8 but less than 12
User Iman
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6.6k points
6 votes
8<t<12 would be your answer buddy :)
User John Elion
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