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How many grams of water are needed to react with 485 g of calcium carbide

User Ginna
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1 Answer

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The procedure for this is the next one:
moles CaC2 = 485 g/64.1 g/mol=7.57
moles H2O = 2 x 7.57 =15.1
mass H2O = 15.1 mol x 18.02 g/mol=272.8 g

User Yuval Perelman
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