Question

A 1.25 m long string attached to a 60.0 Hz vibra

tor created a standing wave with 5 loops. What was the velocity of the waves in the string?


Unit= m/s

Answer 1

The velocity of the waves in the string is 30 m/s.

Step-by-step explanation:

Given;

frequency of the wave, F = 60.0 Hz

number of loops, n = 5

length of the string, L = 1.25 m

1 loop, L = λ/2

For 5 loops;

`L = (5\lambda)/(2)`

where;

λ is the wavelength

`L = (5 \lambda)/(2) \\\\5 \lambda = 2L\\\\\lambda = (2L)/(5) \\\\\lambda = (2 \ * \ 1.25)/(5) \\\\\lambda = 0.5 \ m`

The velocity of the waves in the string is calculated as;

V = Fλ

V = (60)(0.5)

V = 30 m/s

Therefore, the velocity of the waves in the string is 30 m/s.