Question

Say I have a series circuit with 20v and four 65 ohm resistors, what is the current in each resistor?

Answer 1

Data:


`E = 20 V`

`R_(1) = 65\Omega`

`R_(2) = 65\Omega`

`R_(3) = 65\Omega`

`R_(4) = 65\Omega`

Now that we have all the values ​​we need properly identified, simply calculate the equivalent total resistance of the circuit and the intensity of the total electric current using the Ohm's Law:


`R_(T) = R_(1) + R_(2) + R_(3) + R_(4)`

`R_(T) = 65 + 65 + 65+ 65`

`R_(T) = 260\Omega`

Like this:


`I_(T) = (E)/( R_(T) )`


`I_(T) = (20)/( 260 )`

`I_(T) = 0,076923076...`


`\boxed{\boxed{I_(T) \approx 0,07A}}`
Answer:
The intensity of the total electric current

`\boxed{\boxed{I_(T) \approx 0,07A}}`

P.S:. Since the association is in series, the current of 0.07A is the same for all resistors.