Answer:
9 years
Explanation:
Formula for continuous compounding is;
Total amount after the compounding period = P + P[(e^(rt)) - 1]
Where;
P = principal
r is interest rate
t is time period of compounding
We are given;
P = $12,000
Interest rate; r = 7.5% = 0.075
Time; t =?
Amount after investment; $23,568.40
Thus;
23568.40 = 12000(1 + [(e^(0.075t)) - 1])
(1 + [(e^(0.075t)) - 1]) = 23568.40/12000
[(e^(0.075t)) - 1] = (23568.40/12000) - 1
[(e^(0.075t)) - 1] = 0.964
(e^(0.075t)) = 1 + 0.964
(e^(0.075t)) = 1.964
0.075t = In 1.964
0.075t = 0.67498
t = 0.67498/0.075
t = 9 years