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When sec theta=1.75, sin theta=√33/7 , please show me how you get this answer?

When sec theta=1.75, sin theta=√33/7 , please show me how you get this answer?
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When sec theta=1.75, sin theta=√33/7 , please show me how you get this answer?

User Arbrcr
by
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1 Answer

2 votes
Sec is reciprocal of cos.
Sec 1.75 changed to improper fraction 7/4.
Cos theta is 4/7.
Sin is adjacent/hypotenuse
Use Pythagorean theorem to find the missing side of the triangle
4^2+b^2=7^2
b^2=49-16
b= sqrt33
Sin theta = (sqrt33)/7
User Hanh Le
by
7.9k points
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