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Determine the number of moles in 4.00x10^2 g of aluminum sulfate.

User Gauloises
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1 Answer

7 votes
n = m/MM
n: moles
m: mass
MM: molar mass

nAl2(SO4)3 = 400 g / 342.15 g/mol
= 1.16 mol
User Siegel
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