Question

A 3.45 L container has a pressure of 2.14 atm and contains 0.461 mol of gas. What is the temperature inside the container?

100 points!!

Answer 1

the temperature of gas inside the container is 195.2 K.

Step-by-step explanation:

Given;

volume of gas in the container, V = 3.45 L

pressure of gas in the container, P = 2.14 atm

number of gas moles, n = 0.461 mol

The temperature of gas inside the container is calculated as;

`PV = nRT\\\\T = (PV)/(nR)`

where;

R is gas constant = 0.08205 L.atm/mol.K

`T = (2.14 \ * \ 3.45)/(0.461 \ * \ 0.08205) \\\\T = 195.2 \ K`

Therefore, the temperature of gas inside the container is 195.2 K.