a) Suppose that the standard deviation of the population is known to be sigma = 4.5 kg. What is sx, the standard error of x?
δx = δ/√n = 4.5kg / √24 = 4.5kg / 4.90 = 0.918
b) Give a 95% confidence interval for the mean of the population from which the sample is drawn.
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x + z * δ/√n where z* = 1.96 for the 95% confidence interval
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x = Σx / n = 1483/24 = 61.79
61.79 + 1.96(0.918) = between 59.99 kg and 63.59 kg
c) Are you quite sure that the average weight of the population of runners is less than 65 kg?
Based on my computation, 65 kg is above the 95% confidence interval. Thus, the average weight of the population of runners is less than 65 kg.