Question

A student drops a rock from a bridge to the

water 14.4 m below.
With what speed does the rock strike
the water? The acceleration of gravity is
9.8 m/s².
Answer in units of m/s.

Answer 1

Answer: 

Step-by-step explanation:

at first the rock is at rest so initial velocity is zero
after accelerating it reaches a final velocity
we are supposed to find that final velocity



`v^(2) = u^(2) +2ax`
v= final velocity
u= initial velocity
x= distance
a= acceleration


`v^(2) = 0^(2) + 2(9.8)(14.4)`

`v^(2) = 282.24`

`v= √(282.24)`

`v= 16.8 m/s`