Question

A coach throws a football from a height of 4 feet with an initial velocity of 59 feet per second at an elevation angle of 45 degrees. Which parametric equation represents the path of the football

Answer 1

C

Explanation:

Answer 2

`x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2`

Explanation:

From the question we are told that

Height
`h=4feet`

Initial velocity of
`v_0=59 feet/sec`

Angle
`\theta= 40\textdegree`

Generally the parametric equation for projectile motion is mathematically given by

`x=(v_0cos\theta)t,y=y_0+(v_0sin\theta)t-16t^2`

Therefore

`x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2`

The parametric equation that represents the path of the football

`x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2`