Question

How many excess electrons must you add to an object to give it a charge of -6.50 μc?

Answer 1

To give an object a charge of -6.50 μC, you would need to add approximately 4.06 × 10^19 excess electrons.

Step-by-step explanation:

The net charge on an object is determined by dividing the total charge by the charge per electron. In this case, you have a charge of -6.50 μC. Since each electron has a charge of -1.60 × 10^(-19) C, you can calculate the number of excess electrons by dividing the total charge by the charge per electron:

-6.50 μC / (-1.60 × 10^(-19) C/e) = 4.06 × 10^19 electrons

Therefore, you would need to add approximately 4.06 × 10^19 excess electrons to the object to give it a charge of -6.50 μC.

Answer 2

micro = 10^-6
n = nano = 10^-9

(a) -2.5 micro coulombs = -2.5 X 10^-6
The charge on a electron is always -1.60 X 10^-19.

So, given charge divided by charge on electron gives you number of electrons.
(-2.5X10^-6)/(-1.60X10^-19) = 1.5625 X 10^13 excess electrons.

(b) -2.5 nano coulombs = -2.5 X 10^-9
The charge on a electron is always -1.60 X 10^-19.

So, given charge divided by charge on electron gives you number of electrons.
(-2.5X10^-9)/(-1.60X10^-19) = 1.5625 X 10^10 excess electrons.

Round my answers to 3 significant figures if needed or to the appropriate form asked by the question.