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A line passes through the points (7,9) and (10,1). What is its equation in point-slope form?

Use one of the specified points in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.

User MattDiMu
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1 Answer

12 votes
12 votes

Answer:


(y - 9) = (-8/3)\, (x - 7).

Explanation:

If a line in a cartesian plane has slope
m, and the point
(x_(0),\, y_(0)) is on this line, then the point-slope equation of this line will be
(y - y_(0)) = m\, (x - x_(0)).

The slope of a line measures the rate of change in
y-coordinates relative to the change in the
x-coordinates. If a line goes through two points
(x_(0),\, y_(0)) and
(x_(1),\, y_(1)), the slope of that line will be:


\begin{aligned}m &= (y_(1) - y_(0))/(x_(1) - x_(0))\end{aligned}.

In this question, the two points on this line are
(7,\, 9) and
(10,\, 1), such that
x_(0) = 7,
y_(0) = 9,
x_(1) = 10, and
y_(1) = 1. Substitute these values into the equation to find the slope of this line:


\begin{aligned}m &= (y_(1) - y_(0))/(x_(1) - x_(0)) \\ &= (1 - 9)/(10 - 7) \\ &= \left(-(8)/(3)\right)\end{aligned}.

With the point
(7,\, 9) as the specific point
(x_(0),\, y_(0)) (such that
x_(0) = 7 and
y_(0) = 1) as well as a slope of
m = (-8 / 3), the point-slope equation of this line will be:


y - y_(0) = m\, (x - x_(0)).


\displaystyle y - 9 = \left(-(8)/(3)\right)\, (x - 7).

User GalacticRaph
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3.2k points