Answer:
300 m/s
Step-by-step explanation:
Step one:
Given data
Mass of players head m1= 5kg
The initial velocity of players head u1= 3.2m/s
mass of ball m2= 0.5kg
Initial velocity of ball= 5 m/s
Final velocity of player= 2.5 m/s
Required
The velocity of the ball after collision
Step two:
Applying the conservation of momentum formula for elastic collision
m1u1+m2u2= m1v1+m2v2
substitute
5*32+0.5*5= 5*2.5+0.5*v2
160+2.5= 12.5+0.5v2
collect like terms
162.5-12.5= 0.5v2
150= 0.5v2
divide both sides by 0.5
v2= 150/0.5
v2=300 m/s
The new velocity of the ball is 300 m/s