Answer:
2 / 13
Explanation:
Number of cards in a standard deck = 52
Number of 4's = 4 ( 1 for each suit)
Number of 6's = 4 (1 for each suit)
Probability, P = required outcome / Total possible outcomes
P(a 4) = 4 / 52 = 1/ 13
P(a 6) = 4 /52 = 1/13
Probability of either a 4 or a 6
P(a 4) + P(a 6)
1/13 + 1/13
= 2 / 13