Question

A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the final volume of the solution is 508 mL. Group of answer choices

Answer 1

`x_(suc)=0.00406`

Step-by-step explanation:

Hello!

In this case, since the mole fraction relates the moles of solute and the moles of solution, and for sucrose it is:

`x_(suc)=(n_(suc))/(n_(suc)+n_(water))`

Whereas we need to compute the moles of both sucrose and water based on their molar masses (342.3 and 18.02 respectively) as shown below:

`n_(suc)}=(38.6g)/(342.3g/mol)=0.113mol\\\\ n_(water)}=(495g)/(18.02g/mol)=27.5mol\\`

Thus, the mole fraction sucrose turns out:

`x_(suc)=(0.112)/(0.112+27.5)\\\\x_(suc)=0.00406`

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