Question

Which logaritmic graph can be used to approximate the value of y in the equation 4^y=8

Answer 1

By definition, if

`b^y = a`

then

`log_(b)a = y`

In this case, if

`4^(y) = 8`

then

`log_(4) 8 = y`

We have:

`4^(y) = 8`

`2^(2y) = 2^(3)`

`\diagup\!\!\!2^(2y) = \diagup\!\!\!2^(3)`

`2y = 3`

`y = (3)/(2)` or
`y = 1.5`

logaritmic graph (Follows the attachment):