The answer is: 46.8 mg .
________________________________________________________
There are 46.8 mg of calcium in 6 oz. of cooked chicken.
_________________________________________________________
Explanation: To solve:
________________________________________________________
(3.9 mg Ca) / (0.5 oz chicken) = ( "x" mg Ca) / 6 oz cooked chicken ;
___________________________________________________
Find "x" (in "mg", or "milligrams").
_____________________________
→ (3.9)/(0.5) = x/ 6
___________________________________
→ (0.5)x = (3.9) * (6) ;
_____________________________
→ (0.5) x = 23.4 ;
_________________________
→ Now, divide EACH side of the equation by "(0.5)", to isolate "x" on one side of the equation; and to solve for x:
_________________________________
→ (0.5) x / (0.5) = 23.4 / (0.5) ;
_________________________________
→ x = 46.8 mg Ca____________________________