Question

Consider that the half-life of Polonium-210 is 140 days.What approximate daily percentage of decay does Polonium-210 demonstrate?% (Round to two decimals.)(Hint: use the Rule of 70 backwards by dividing by the half-life period instead of the rate.) What percentage of the original amount of Polonium-210 would be left after 425 days of decay? % (Round to two decimals.)

Answer 1

For the answer to the question above, the decay function is F = A(0.5)^(t/140) where A is the initial amount of Polonium-210 and F is the remaining amount after t days of decay.

So F/A = (0.5)^(425/140) = (0.5)^3.035… = 0.12194… = 12.194%

Therefore F = 12.194%
i hope this helps