Question

Consider the following chemical reaction:

4HCl + MnO2 → MnCl2 + 2H2O + Cl2 .

When 0.268 mol of HCl reacts stoichiometrically with MnO2, how many grams of Cl2 is produced?

Answer 1

Here's your solution. Hope it helps.

Answer 2

According to the equation, the ratio of
`HC\ell` to
`C\ell_2` is
`4:1`. Then:


`(n_(HC\ell))/(n_(C\ell_2))=(4)/(1)\Longrightarrow(0.268)/(n_(C\ell_2))=(4)/(1)\Longrightarrow n_(C\ell_2)=(0.268)/(4)\iff n_(C\ell_2)=0.067~mol`

Now we can calculate the mass of
`C\ell_2` formed.


`m_(C\ell_2)=n_(C\ell_2)\cdot MM_(C\ell_2)\Longrightarrow m_(C\ell_2)=0.067\cdot(2\cdot35.5)\Longrightarrow\\\\ m_(C\ell_2)=0.067\cdot71\Longrightarrow\boxed{m_(C\ell_2)=4.757~g}`