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How do I solve for d in the following equation? c(ad)+x=bd+ad(yz)

1 Answer

6 votes
easy
remember associative property
a(bc)=(ab)c
so theerfor we can move dem around
also rembmer distributive property and how it can be expanded
ab+ac=a(b+c) therefor
ab+ac+ad=a(b+c+d)

(ca)d+x=bd+d(ayz)
minus (ca)d from both sides
x=db+d(ayz)-d(ca)
undistribute d
x=d(b+ayz-ca)
divide both sides by (b+ayz-ca)

(x)/(b+ayz-ca)=d

d=(x)/(b+ayz-ca)
User Yaje
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