Answer:
1300 kcal
this is the right answer, i had this question
To solve the problem, we must know the heat capacity of ice and water.
For Cp = 2090 J/kg C
H = mCpT
H = (10 kg) ( 2090 J/ Kg C) ( -23 C)
H = - 480700 J
For water Cp = 4180 j/kg C
H = (100 kg) ( 4180 J/kg C) ( 60 C)
H = 2508000 J
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