Answer:
1/3 and (0,1)
Explanation:
In a cartesian plane, we can represent a line using a general equation defined in that plane. Given a line with slope
and a point which it passes through
it is possible to obtain the equation of the line from the of the slope-intercept form:

Where:

From the graph provided by the problem we can extract the two points we need.
Let:

Thus:


Now that we know the slope and the equation of the graph, we can easily find the y-intercept of the line. Actually you can conclude what is the y-intercept just by looking the graph, as you can see, the line crosses the y-axis at the point (0,1). However, let's find it using the equation that we found. As you may know, the line will cross the y-axis when x=0, so let's evaluate the function for x=0:

Therefore, the y-intercept of the line is (0,1).