Question

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and hotdogs and made $420. How many of each did they sell?

What solution is reasonable?
Question 3 options:


200 hamburgers and 50 hotdogs


50 hamburgers and 200 hotdogs


120 hamburgers and 180 hotdogs


100 hamburgers and 180 hotdogs

I think the answer is 120 hamburgers and 180 hotdogs ,but I'm not sure.Thanks to whoever helps me .

Answer 1

120 hamburgers and 180 hot dogs.

Answer 2

Answer: 120 hamburgers and 180 hotdogs

Explanation:

Let 'x' be the number of hamburgers and 'y' be the number of hotdogs sold.

Then, the total number of hamburgers and hotdogs sold on friday will be given by :_

`x+y=300.....................(1)`

On the basis of their cost, the total cost will be:-

`2x+y=420..............................(2)`

Subtract (1) from (2), we get

`x=120`

Substitute the value of x in (1), we get

`120+y=300\\\Rightarrow y=300-120\\\Rightarrow y=180`

Hence, they sold 120 hamburgers and 180 hotdogs.