224k views
3 votes
Suppose you pick 4 cards randomly from a well-shuffled standard deck of 52 playing cards.

The probability that you draw the 2, 4, 6, and 8 of spades in that order is

Answer choices:
1/6, 497, 400
1/380, 204, 032
1/311, 875, 200

User Gzaxx
by
8.3k points

2 Answers

3 votes
1/52 x 1/51 x 1/50 x 1/49
= 1/ 6,497,400
User Jedmao
by
8.7k points
5 votes

Answer:

The probability is:

1/6, 497, 400

Explanation:

We are given that:

We pick 4 cards randomly from a well-shuffled standard deck of 52 playing cards.

We are asked to find the probability such that:

We draw 2, 4, 6, and 8 of spades in that order.

i.e. firstly we have to draw a 2 of a spade.

at second turn we have to draw a 4 of a spade.

at third turn we have to draw a 6 of a spade.

at the last draw we have to draw 8 of a spade.

As there are total 52 cards.

The probability of drawing a 2 of a spade at first turn= 1/52.

The probability of drawing a 4 of a spade at second turn= 1/51.

( since 1 card has been drawn out in the first turn).

The probability of drawing a 6 of a spade at third turn= 1/50.

The probability of drawing a 8 of a spade at fourth turn= 1/49

Hence, the total probability that you draw the 2, 4, 6, and 8 of spades in that order is :


=(1)/(52)* (1)/(51)* (1)/(50)* (1)/(49)\\ \\\\=(1)/(6497400)

User Thestral
by
8.8k points