Question

a spring has a constant of 53 N/m. how much elastic potential energy is stored in the spring when it is compressed by 0.21m?

Answer 1

1.17 J

Step-by-step explanation:

just did it and it was correct

Answer 2

Data:

`E_(ep) = ?` (The SI unit of potential energy is the joule)

`k = 53 N/m`

`x = 0,21m` →
`x = 2,1 * 10^(-1)m`

Formula:

`E_(ep) = (k*x^2)/(2)`

Solving:

`E_(ep) = (k*x^2)/(2)`


`E_(ep) = (53*(2,1 * 10^(-1))^2)/(2)`


`E_(ep) = (53*4,41 * 100^(-1))/(2)`


`E_(ep) = (233,73 * (1)/(100) )/(2)`


`E_(ep) = ( (233,73)/(100) )/(2)`


`E_(ep) = \frac{ {2.3373} }{2}`


`\boxed{E_(ep) = 1.16865J}`