Question

Atiya rolls a 7.0 kg bowling ball down the

alley for the championship. One pin is still

standing, and Atiya hits it head-on with a

velocity of 9.0 m/s. The 2.0 kg pin moved

forward with a velocity of 14.0 m/s. What is

the new velocity of the bowling ball?

Answer 1

5 m/s

Explanation:

According to law of conservation of momentum :

m1u1 + m2u2 = m1v1 + m2v1

m1 = 7kg ; u1 = 9m/s ; m2 = 2kg ; u2 = 0 ; v2 = 14 m/s

m = masses ; u = initial velocities ; v = final velocities

m1u1 + m2u2 = m1v1 + m2v1

7*9 + 2*0 = 7*v + 2*14

63 + 0 = 7v1 + 28

63 = 7v1 + 28

63 - 28 = 7v1

35 = 7v1

v1 = 35 / 7

v1 = 5 m/s